(3x)+(x+4)+x=72

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Solution for (3x)+(x+4)+x=72 equation: 



(3x)+(x+4)+x=72

We move all terms to the left:

(3x)+(x+4)+x-(72)=0

We add all the numbers together, and all the variables

4x+(x+4)-72=0

We get rid of parentheses

4x+x+4-72=0

We add all the numbers together, and all the variables

5x-68=0

We move all terms containing x to the left, all other terms to the right

5x=68

x=68/5

x=13+3/5

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