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(3x)+(5x-2)=3(x+3)
We move all terms to the left:
(3x)+(5x-2)-(3(x+3))=0
We get rid of parentheses
3x+5x-(3(x+3))-2=0
We calculate terms in parentheses: -(3(x+3)), so:We add all the numbers together, and all the variables
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
8x-(3x+9)-2=0
We get rid of parentheses
8x-3x-9-2=0
We add all the numbers together, and all the variables
5x-11=0
We move all terms containing x to the left, all other terms to the right
5x=11
x=11/5
x=2+1/5
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