(3x)+(4x+19)=131

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Solution for (3x)+(4x+19)=131 equation: 



(3x)+(4x+19)=131

We move all terms to the left:

(3x)+(4x+19)-(131)=0

We get rid of parentheses

3x+4x+19-131=0

We add all the numbers together, and all the variables

7x-112=0

We move all terms containing x to the left, all other terms to the right

7x=112

x=112/7

x=16

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