(3w-15)/((1/w)-(1/5))

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Solution for (3w-15)/((1/w)-(1/5)) equation:


D( w )

1/w-(1/5) = 0

w = 0

1/w-(1/5) = 0

1/w-(1/5) = 0

1/w-1/5 = 0

1*w^-1 = 1/5 // : 1

w^-1 = 1/5

-1 < 0

1/(w^1) = 1/5 // * w^1

1 = 1/5*w^1 // : 1/5

5 = w^1

w = 5

w = 0

w = 0

w in (-oo:0) U (0:5) U (5:+oo)

(3*w-15)/(1/w-(1/5)) = 0

(3*w-15)/(1/w-1/5) = 0

(3*w-15)/(w^-1-1/5) = 0

3*w-15 = 0 // + 15

3*w = 15 // : 3

w = 15/3

w = 5

w in { 5}

w belongs to the empty set

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