(3w+7)(6+w)=0

Solution for (3w+7)(6+w)=0 equation:

(3w+7)(6+w)=0

We add all the numbers together, and all the variables

(3w+7)(w+6)=0

We multiply parentheses ..

(+3w^2+18w+7w+42)=0

We get rid of parentheses

3w^2+18w+7w+42=0

We add all the numbers together, and all the variables

3w^2+25w+42=0

a = 3; b = 25; c = +42;
Δ = b2-4ac
Δ = 252-4·3·42
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-11}{2*3}=\frac{-36}{6}
=-6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+11}{2*3}=\frac{-14}{6}
=-2+1/3
$