(3v-1)(v=3)

Solution for (3v-1)(v=3) equation:

(3v-1)(v=3)

We move all terms to the left:

(3v-1)(v-(3))=0

We multiply parentheses ..

(+3v^2-9v-1v+3)=0

We get rid of parentheses

3v^2-9v-1v+3=0

We add all the numbers together, and all the variables

3v^2-10v+3=0

a = 3; b = -10; c = +3;
Δ = b2-4ac
Δ = -102-4·3·3
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-8}{2*3}=\frac{2}{6}
=1/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+8}{2*3}=\frac{18}{6}
=3
$