(3v+8)(3-v)=0

Solution for (3v+8)(3-v)=0 equation:

(3v+8)(3-v)=0

We add all the numbers together, and all the variables

(3v+8)(-1v+3)=0

We multiply parentheses ..

(-3v^2+9v-8v+24)=0

We get rid of parentheses

-3v^2+9v-8v+24=0

We add all the numbers together, and all the variables

-3v^2+v+24=0

a = -3; b = 1; c = +24;
Δ = b2-4ac
Δ = 12-4·(-3)·24
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-17}{2*-3}=\frac{-18}{-6}
=+3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+17}{2*-3}=\frac{16}{-6}
=-2+2/3
$