(3v+5)(6-v)=0

Solution for (3v+5)(6-v)=0 equation:

(3v+5)(6-v)=0

We add all the numbers together, and all the variables

(3v+5)(-1v+6)=0

We multiply parentheses ..

(-3v^2+18v-5v+30)=0

We get rid of parentheses

-3v^2+18v-5v+30=0

We add all the numbers together, and all the variables

-3v^2+13v+30=0

a = -3; b = 13; c = +30;
Δ = b2-4ac
Δ = 132-4·(-3)·30
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-23}{2*-3}=\frac{-36}{-6}
=+6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+23}{2*-3}=\frac{10}{-6}
=-1+2/3
$