(3u+5/2)=(6u+2/5)+3

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Solution for (3u+5/2)=(6u+2/5)+3 equation: 


u in (-oo:+oo)

3*u+5/2 = 6*u+2/5+3 // - 6*u+2/5+3

3*u-(6*u)+5/2-(2/5)-3 = 0

3*u-6*u+5/2-2/5-3 = 0

-3*u-9/10 = 0 // + 9/10

-3*u = 9/10 // : -3

u = 9/10/(-3)

u = -3/10

u = -3/10

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