(3u+25)(8u+3)=0

Solution for (3u+25)(8u+3)=0 equation:

(3u+25)(8u+3)=0

We multiply parentheses ..

(+24u^2+9u+200u+75)=0

We get rid of parentheses

24u^2+9u+200u+75=0

We add all the numbers together, and all the variables

24u^2+209u+75=0

a = 24; b = 209; c = +75;
Δ = b2-4ac
Δ = 2092-4·24·75
Δ = 36481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36481}=191$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(209)-191}{2*24}=\frac{-400}{48}
=-8+1/3
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(209)+191}{2*24}=\frac{-18}{48}
=-3/8
$