(3u+2)(5+u)=0

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Solution for (3u+2)(5+u)=0 equation:


Simplifying
(3u + 2)(5 + u) = 0

Reorder the terms:
(2 + 3u)(5 + u) = 0

Multiply (2 + 3u) * (5 + u)
(2(5 + u) + 3u * (5 + u)) = 0
((5 * 2 + u * 2) + 3u * (5 + u)) = 0
((10 + 2u) + 3u * (5 + u)) = 0
(10 + 2u + (5 * 3u + u * 3u)) = 0
(10 + 2u + (15u + 3u2)) = 0

Combine like terms: 2u + 15u = 17u
(10 + 17u + 3u2) = 0

Solving
10 + 17u + 3u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(5 + u)(2 + 3u) = 0

Subproblem 1

Set the factor '(5 + u)' equal to zero and attempt to solve: Simplifying 5 + u = 0 Solving 5 + u = 0 Move all terms containing u to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + u = 0 + -5 Combine like terms: 5 + -5 = 0 0 + u = 0 + -5 u = 0 + -5 Combine like terms: 0 + -5 = -5 u = -5 Simplifying u = -5

Subproblem 2

Set the factor '(2 + 3u)' equal to zero and attempt to solve: Simplifying 2 + 3u = 0 Solving 2 + 3u = 0 Move all terms containing u to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 3u = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 3u = 0 + -2 3u = 0 + -2 Combine like terms: 0 + -2 = -2 3u = -2 Divide each side by '3'. u = -0.6666666667 Simplifying u = -0.6666666667

Solution

u = {-5, -0.6666666667}

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