(3t-2)/3+(2t+3)/2=t+7/6

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Solution for (3t-2)/3+(2t+3)/2=t+7/6 equation: 



(3t-2)/3+(2t+3)/2=t+7/6

We move all terms to the left:

(3t-2)/3+(2t+3)/2-(t+7/6)=0

We add all the numbers together, and all the variables

(3t-2)/3+(2t+3)/2-(+t+7/6)=0

We get rid of parentheses

(3t-2)/3+(2t+3)/2-t-7/6=0

We calculate fractions

There is no solution for this equation

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