(3r+9)/6=(4r-12)/4

Solution for (3r+9)/6=(4r-12)/4 equation:

(3r+9)/6=(4r-12)/4

We move all terms to the left:

(3r+9)/6-((4r-12)/4)=0

We calculate fractions


3r/()+(-((4r-12)*6)/()=0


We calculate terms in parentheses: +(-((4r-12)*6)/(), so:

-((4r-12)*6)/(

We multiply all the terms by the denominator


-((4r-12)*6)


We calculate terms in parentheses: -((4r-12)*6), so:

(4r-12)*6

We multiply parentheses

24r-72

Back to the equation:

-(24r-72)


We get rid of parentheses

-24r+72

Back to the equation:

+(-24r+72)


We get rid of parentheses

3r/()-24r+72=0

We multiply all the terms by the denominator


3r-24r*()+72*()=0

We add all the numbers together, and all the variables

3r-24r*()=0