(3q+1)+4=3(q+4)-7

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Solution for (3q+1)+4=3(q+4)-7 equation:



(3q+1)+4=3(q+4)-7
We move all terms to the left:
(3q+1)+4-(3(q+4)-7)=0
We get rid of parentheses
3q-(3(q+4)-7)+1+4=0
We calculate terms in parentheses: -(3(q+4)-7), so:
3(q+4)-7
We multiply parentheses
3q+12-7
We add all the numbers together, and all the variables
3q+5
Back to the equation:
-(3q+5)
We add all the numbers together, and all the variables
3q-(3q+5)+5=0
We get rid of parentheses
3q-3q-5+5=0
We add all the numbers together, and all the variables
=0
q=0/1
q=0

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