(3n/10)-(n/5)=(1/2)

Solution for (3n/10)-(n/5)=(1/2) equation:

(3n/10)-(n/5)=(1/2)

We move all terms to the left:

(3n/10)-(n/5)-((1/2))=0

We add all the numbers together, and all the variables

(+3n/10)-(+n/5)-((+1/2))=0

We get rid of parentheses

3n/10-n/5-((+1/2))=0

We calculate fractions


(-40n^2)/()+60n^2/()+()/()=0

We add all the numbers together, and all the variables

(-40n^2)/()+60n^2/()+1=0

We multiply all the terms by the denominator


(-40n^2)+60n^2+1*()=0

We add all the numbers together, and all the variables

60n^2+(-40n^2)=0

We get rid of parentheses

60n^2-40n^2=0

We add all the numbers together, and all the variables

20n^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{40}=0$