(3n-2)/7=(n+6)/4

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Solution for (3n-2)/7=(n+6)/4 equation: 



(3n-2)/7=(n+6)/4

We move all terms to the left:

(3n-2)/7-((n+6)/4)=0

We calculate fractions


3n/()+(-((n+6)*7)/()=0



We calculate terms in parentheses: +(-((n+6)*7)/(), so:

-((n+6)*7)/(

We multiply all the terms by the denominator


-((n+6)*7)



We calculate terms in parentheses: -((n+6)*7), so:

(n+6)*7

We multiply parentheses

7n+42

Back to the equation:

-(7n+42)



We get rid of parentheses

-7n-42

Back to the equation:

+(-7n-42)



We get rid of parentheses

3n/()-7n-42=0

We multiply all the terms by the denominator


3n-7n*()-42*()=0

We add all the numbers together, and all the variables

3n-7n*()=0

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