(3m-3)/5=(2m-1)/2

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Solution for (3m-3)/5=(2m-1)/2 equation: 



(3m-3)/5=(2m-1)/2

We move all terms to the left:

(3m-3)/5-((2m-1)/2)=0

We calculate fractions


3m/()+(-((2m-1)*5)/()=0



We calculate terms in parentheses: +(-((2m-1)*5)/(), so:

-((2m-1)*5)/(

We multiply all the terms by the denominator


-((2m-1)*5)



We calculate terms in parentheses: -((2m-1)*5), so:

(2m-1)*5

We multiply parentheses

10m-5

Back to the equation:

-(10m-5)



We get rid of parentheses

-10m+5

Back to the equation:

+(-10m+5)



We get rid of parentheses

3m/()-10m+5=0

We multiply all the terms by the denominator


3m-10m*()+5*()=0

We add all the numbers together, and all the variables

3m-10m*()=0

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