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(3m+6)(2m+9)=5+(-3)
We move all terms to the left:
(3m+6)(2m+9)-(5+(-3))=0
We add all the numbers together, and all the variables
(3m+6)(2m+9)-2=0
We multiply parentheses ..
(+6m^2+27m+12m+54)-2=0
We get rid of parentheses
6m^2+27m+12m+54-2=0
We add all the numbers together, and all the variables
6m^2+39m+52=0
a = 6; b = 39; c = +52;
Δ = b2-4ac
Δ = 392-4·6·52
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-\sqrt{273}}{2*6}=\frac{-39-\sqrt{273}}{12} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+\sqrt{273}}{2*6}=\frac{-39+\sqrt{273}}{12} $
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