(3m+5)(m-4)=(3m+5)(m)-(3m+5)(4)

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Solution for (3m+5)(m-4)=(3m+5)(m)-(3m+5)(4) equation: 



(3m+5)(m-4)=(3m+5)(m)-(3m+5)(4)

We move all terms to the left:

(3m+5)(m-4)-((3m+5)(m)-(3m+5)(4))=0

We multiply parentheses ..

(+3m^2-12m+5m-20)-((3m+5)m-(3m+5)4)=0



We calculate terms in parentheses: -((3m+5)m-(3m+5)4), so:

(3m+5)m-(3m+5)4

We multiply parentheses

3m^2+5m-12m-20

We add all the numbers together, and all the variables

3m^2-7m-20

Back to the equation:

-(3m^2-7m-20)



We get rid of parentheses

3m^2-3m^2-12m+5m+7m-20+20=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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