(3k+30)=(95-k)+(2k-5)

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Solution for (3k+30)=(95-k)+(2k-5) equation: 



(3k+30)=(95-k)+(2k-5)

We move all terms to the left:

(3k+30)-((95-k)+(2k-5))=0

We add all the numbers together, and all the variables

(3k+30)-((-1k+95)+(2k-5))=0

We get rid of parentheses

3k-((-1k+95)+(2k-5))+30=0



We calculate terms in parentheses: -((-1k+95)+(2k-5)), so:

(-1k+95)+(2k-5)

We get rid of parentheses

-1k+2k+95-5

We add all the numbers together, and all the variables

k+90

Back to the equation:

-(k+90)



We get rid of parentheses

3k-k-90+30=0

We add all the numbers together, and all the variables

2k-60=0

We move all terms containing k to the left, all other terms to the right

2k=60

k=60/2

k=30

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