(3i)=(4-i)

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Solution for (3i)=(4-i) equation:



(3i)=(4-i)
We move all terms to the left:
(3i)-((4-i))=0
We add all the numbers together, and all the variables
3i-((-1i+4))=0
We calculate terms in parentheses: -((-1i+4)), so:
(-1i+4)
We get rid of parentheses
-1i+4
Back to the equation:
-(-1i+4)
We get rid of parentheses
3i+1i-4=0
We add all the numbers together, and all the variables
4i-4=0
We move all terms containing i to the left, all other terms to the right
4i=4
i=4/4
i=1

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