(3h+2)+(2h+1)+7h=27

Solution for (3h+2)+(2h+1)+7h=27 equation:

Simplifying
(3h + 2) + (2h + 1) + 7h = 27

Reorder the terms:
(2 + 3h) + (2h + 1) + 7h = 27

Remove parenthesis around (2 + 3h)
2 + 3h + (2h + 1) + 7h = 27

Reorder the terms:
2 + 3h + (1 + 2h) + 7h = 27

Remove parenthesis around (1 + 2h)
2 + 3h + 1 + 2h + 7h = 27

Reorder the terms:
2 + 1 + 3h + 2h + 7h = 27

Combine like terms: 2 + 1 = 3
3 + 3h + 2h + 7h = 27

Combine like terms: 3h + 2h = 5h
3 + 5h + 7h = 27

Combine like terms: 5h + 7h = 12h
3 + 12h = 27

Solving
3 + 12h = 27

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 12h = 27 + -3

Combine like terms: 3 + -3 = 0
0 + 12h = 27 + -3
12h = 27 + -3

Combine like terms: 27 + -3 = 24
12h = 24

Divide each side by '12'.
h = 2

Simplifying
h = 2