(3g-4)+(4g+10)=99

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Solution for (3g-4)+(4g+10)=99 equation: 



(3g-4)+(4g+10)=99

We move all terms to the left:

(3g-4)+(4g+10)-(99)=0

We get rid of parentheses

3g+4g-4+10-99=0

We add all the numbers together, and all the variables

7g-93=0

We move all terms containing g to the left, all other terms to the right

7g=93

g=93/7

g=13+2/7

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