(3d/6)=((3/9)

Solution for (3d/6)=((3/9) equation:

(3d/6)=((3/9)

We move all terms to the left:

(3d/6)-(((3/9))=0

We add all the numbers together, and all the variables

(+3d/6)-(((+3/9))=0

We get rid of parentheses

3d/6-(((+3/9))=0

We calculate fractions


27d^2/()+()/()=0

We add all the numbers together, and all the variables

27d^2/()+1=0

We multiply all the terms by the denominator


27d^2+1*()=0

We add all the numbers together, and all the variables

27d^2=0

a = 27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·27·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{54}=0$