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Simplifying (3c + -3)(3c + -3) = 0 Reorder the terms: (-3 + 3c)(3c + -3) = 0 Reorder the terms: (-3 + 3c)(-3 + 3c) = 0 Multiply (-3 + 3c) * (-3 + 3c) (-3(-3 + 3c) + 3c * (-3 + 3c)) = 0 ((-3 * -3 + 3c * -3) + 3c * (-3 + 3c)) = 0 ((9 + -9c) + 3c * (-3 + 3c)) = 0 (9 + -9c + (-3 * 3c + 3c * 3c)) = 0 (9 + -9c + (-9c + 9c2)) = 0 Combine like terms: -9c + -9c = -18c (9 + -18c + 9c2) = 0 Solving 9 + -18c + 9c2 = 0 Solving for variable 'c'. Factor out the Greatest Common Factor (GCF), '9'. 9(1 + -2c + c2) = 0 Factor a trinomial. 9((1 + -1c)(1 + -1c)) = 0 Ignore the factor 9.Subproblem 1
Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1Solution
c = {1, 1}
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