(3c-15)+(9c-19)+(c+19)=180

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Solution for (3c-15)+(9c-19)+(c+19)=180 equation:


Simplifying
(3c + -15) + (9c + -19) + (c + 19) = 180

Reorder the terms:
(-15 + 3c) + (9c + -19) + (c + 19) = 180

Remove parenthesis around (-15 + 3c)
-15 + 3c + (9c + -19) + (c + 19) = 180

Reorder the terms:
-15 + 3c + (-19 + 9c) + (c + 19) = 180

Remove parenthesis around (-19 + 9c)
-15 + 3c + -19 + 9c + (c + 19) = 180

Reorder the terms:
-15 + 3c + -19 + 9c + (19 + c) = 180

Remove parenthesis around (19 + c)
-15 + 3c + -19 + 9c + 19 + c = 180

Reorder the terms:
-15 + -19 + 19 + 3c + 9c + c = 180

Combine like terms: -15 + -19 = -34
-34 + 19 + 3c + 9c + c = 180

Combine like terms: -34 + 19 = -15
-15 + 3c + 9c + c = 180

Combine like terms: 3c + 9c = 12c
-15 + 12c + c = 180

Combine like terms: 12c + c = 13c
-15 + 13c = 180

Solving
-15 + 13c = 180

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 13c = 180 + 15

Combine like terms: -15 + 15 = 0
0 + 13c = 180 + 15
13c = 180 + 15

Combine like terms: 180 + 15 = 195
13c = 195

Divide each side by '13'.
c = 15

Simplifying
c = 15

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