(3c+4)=8(c-2)

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Solution for (3c+4)=8(c-2) equation: 



(3c+4)=8(c-2)

We move all terms to the left:

(3c+4)-(8(c-2))=0

We get rid of parentheses

3c-(8(c-2))+4=0



We calculate terms in parentheses: -(8(c-2)), so:

8(c-2)

We multiply parentheses

8c-16

Back to the equation:

-(8c-16)



We get rid of parentheses

3c-8c+16+4=0

We add all the numbers together, and all the variables

-5c+20=0

We move all terms containing c to the left, all other terms to the right

-5c=-20

c=-20/-5

c=+4

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