(3c+4)=(11+2c)

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Solution for (3c+4)=(11+2c) equation: 



(3c+4)=(11+2c)

We move all terms to the left:

(3c+4)-((11+2c))=0

We add all the numbers together, and all the variables

(3c+4)-((2c+11))=0

We get rid of parentheses

3c-((2c+11))+4=0



We calculate terms in parentheses: -((2c+11)), so:

(2c+11)

We get rid of parentheses

2c+11

Back to the equation:

-(2c+11)



We get rid of parentheses

3c-2c-11+4=0

We add all the numbers together, and all the variables

c-7=0

We move all terms containing c to the left, all other terms to the right

c=7

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