(3c+1)-2(c+1)=2

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Solution for (3c+1)-2(c+1)=2 equation:


Simplifying
(3c + 1) + -2(c + 1) = 2

Reorder the terms:
(1 + 3c) + -2(c + 1) = 2

Remove parenthesis around (1 + 3c)
1 + 3c + -2(c + 1) = 2

Reorder the terms:
1 + 3c + -2(1 + c) = 2
1 + 3c + (1 * -2 + c * -2) = 2
1 + 3c + (-2 + -2c) = 2

Reorder the terms:
1 + -2 + 3c + -2c = 2

Combine like terms: 1 + -2 = -1
-1 + 3c + -2c = 2

Combine like terms: 3c + -2c = 1c
-1 + 1c = 2

Solving
-1 + 1c = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 1c = 2 + 1

Combine like terms: -1 + 1 = 0
0 + 1c = 2 + 1
1c = 2 + 1

Combine like terms: 2 + 1 = 3
1c = 3

Divide each side by '1'.
c = 3

Simplifying
c = 3

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