(3c+1)(c-2)=

Solution for (3c+1)(c-2)= equation:

Simplifying
(3c + 1)(c + -2) = 0

Reorder the terms:
(1 + 3c)(c + -2) = 0

Reorder the terms:
(1 + 3c)(-2 + c) = 0

Multiply (1 + 3c) * (-2 + c)
(1(-2 + c) + 3c * (-2 + c)) = 0
((-2 * 1 + c * 1) + 3c * (-2 + c)) = 0
((-2 + 1c) + 3c * (-2 + c)) = 0
(-2 + 1c + (-2 * 3c + c * 3c)) = 0
(-2 + 1c + (-6c + 3c2)) = 0

Combine like terms: 1c + -6c = -5c
(-2 + -5c + 3c2) = 0

Solving
-2 + -5c + 3c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-1 + -3c)(2 + -1c) = 0

Subproblem 1
Set the factor '(-1 + -3c)' equal to zero and attempt to solve:

Simplifying
-1 + -3c = 0

Solving
-1 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -3c = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -3c = 0 + 1
-3c = 0 + 1

Combine like terms: 0 + 1 = 1
-3c = 1

Divide each side by '-3'.
c = -0.3333333333

Simplifying
c = -0.3333333333
Subproblem 2
Set the factor '(2 + -1c)' equal to zero and attempt to solve:

Simplifying
2 + -1c = 0

Solving
2 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1c = 0 + -2
-1c = 0 + -2

Combine like terms: 0 + -2 = -2
-1c = -2

Divide each side by '-1'.
c = 2

Simplifying
c = 2
Solution
c = {-0.3333333333, 2}