(3c)+(6c+1)=-3c+1

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Solution for (3c)+(6c+1)=-3c+1 equation:



(3c)+(6c+1)=-3c+1
We move all terms to the left:
(3c)+(6c+1)-(-3c+1)=0
We get rid of parentheses
3c+6c+3c+1-1=0
We add all the numbers together, and all the variables
12c=0
c=0/12
c=0

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