(3b-4)3=6(b-1)

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Solution for (3b-4)3=6(b-1) equation: 



(3b-4)3=6(b-1)

We move all terms to the left:

(3b-4)3-(6(b-1))=0

We multiply parentheses

9b-(6(b-1))-12=0



We calculate terms in parentheses: -(6(b-1)), so:

6(b-1)

We multiply parentheses

6b-6

Back to the equation:

-(6b-6)



We get rid of parentheses

9b-6b+6-12=0

We add all the numbers together, and all the variables

3b-6=0

We move all terms containing b to the left, all other terms to the right

3b=6

b=6/3

b=2

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