(3b-4)/5=(b-4)/15

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Solution for (3b-4)/5=(b-4)/15 equation: 



(3b-4)/5=(b-4)/15

We move all terms to the left:

(3b-4)/5-((b-4)/15)=0

We calculate fractions


3b/()+(-((b-4)*5)/()=0



We calculate terms in parentheses: +(-((b-4)*5)/(), so:

-((b-4)*5)/(

We multiply all the terms by the denominator


-((b-4)*5)



We calculate terms in parentheses: -((b-4)*5), so:

(b-4)*5

We multiply parentheses

5b-20

Back to the equation:

-(5b-20)



We get rid of parentheses

-5b+20

Back to the equation:

+(-5b+20)



We get rid of parentheses

3b/()-5b+20=0

We multiply all the terms by the denominator


3b-5b*()+20*()=0

We add all the numbers together, and all the variables

3b-5b*()=0

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