(3b-4)(7b+4)=(3b-4)(7b+4)

Solution for (3b-4)(7b+4)=(3b-4)(7b+4) equation:

(3b-4)(7b+4)=(3b-4)(7b+4)

We move all terms to the left:

(3b-4)(7b+4)-((3b-4)(7b+4))=0

We multiply parentheses ..

(+21b^2+12b-28b-16)-((+21b^2+12b-28b-16))=0


We calculate terms in parentheses: -((+21b^2+12b-28b-16)), so:

(+21b^2+12b-28b-16)

We get rid of parentheses

21b^2+12b-28b-16

We add all the numbers together, and all the variables

21b^2-16b-16

Back to the equation:

-(21b^2-16b-16)


We get rid of parentheses

21b^2-21b^2+12b-28b+16b-16+16=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0