(3b-2)/2=(b-5)/6

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Solution for (3b-2)/2=(b-5)/6 equation: 


b in (-oo:+oo)

(3*b-2)/2 = (b-5)/6 // - (b-5)/6

(3*b-2)/2-((b-5)/6) = 0

(3*b-2)/2+(-1*(b-5))/6 = 0

(6*(3*b-2))/(2*6)+(-1*2*(b-5))/(2*6) = 0

6*(3*b-2)-1*2*(b-5) = 0

16*b-2 = 0

(16*b-2)/(2*6) = 0

(16*b-2)/(2*6) = 0 // * 2*6

16*b-2 = 0

16*b-2 = 0 // + 2

16*b = 2 // : 16

b = 2/16

b = 1/8

b = 1/8

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