(3a-b+c)-(2b+c)=0

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Solution for (3a-b+c)-(2b+c)=0 equation:


Simplifying
(3a + -1b + c) + -1(2b + c) = 0

Remove parenthesis around (3a + -1b + c)
3a + -1b + c + -1(2b + c) = 0
3a + -1b + c + (2b * -1 + c * -1) = 0
3a + -1b + c + (-2b + -1c) = 0

Reorder the terms:
3a + -1b + -2b + c + -1c = 0

Combine like terms: -1b + -2b = -3b
3a + -3b + c + -1c = 0

Combine like terms: c + -1c = 0
3a + -3b + 0 = 0
3a + -3b = 0

Solving
3a + -3b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '3b' to each side of the equation.
3a + -3b + 3b = 0 + 3b

Combine like terms: -3b + 3b = 0
3a + 0 = 0 + 3b
3a = 0 + 3b
Remove the zero:
3a = 3b

Divide each side by '3'.
a = b

Simplifying
a = b

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