(3a+4)(3a+2)=(3a+4)

Solution for (3a+4)(3a+2)=(3a+4) equation:

(3a+4)(3a+2)=(3a+4)

We move all terms to the left:

(3a+4)(3a+2)-((3a+4))=0

We multiply parentheses ..

(+9a^2+6a+12a+8)-((3a+4))=0


We calculate terms in parentheses: -((3a+4)), so:

(3a+4)

We get rid of parentheses

3a+4

Back to the equation:

-(3a+4)


We get rid of parentheses

9a^2+6a+12a-3a+8-4=0

We add all the numbers together, and all the variables

9a^2+15a+4=0

a = 9; b = 15; c = +4;
Δ = b2-4ac
Δ = 152-4·9·4
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-9}{2*9}=\frac{-24}{18}
=-1+1/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+9}{2*9}=\frac{-6}{18}
=-1/3
$