(3a+2)+(3a+2)+(a+5)=58

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Solution for (3a+2)+(3a+2)+(a+5)=58 equation: 



(3a+2)+(3a+2)+(a+5)=58

We move all terms to the left:

(3a+2)+(3a+2)+(a+5)-(58)=0

We get rid of parentheses

3a+3a+a+2+2+5-58=0

We add all the numbers together, and all the variables

7a-49=0

We move all terms containing a to the left, all other terms to the right

7a=49

a=49/7

a=7

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