(3a+2)(6a=5)

Solution for (3a+2)(6a=5) equation:

(3a+2)(6a=5)

We move all terms to the left:

(3a+2)(6a-(5))=0

We multiply parentheses ..

(+18a^2-15a+12a-10)=0

We get rid of parentheses

18a^2-15a+12a-10=0

We add all the numbers together, and all the variables

18a^2-3a-10=0

a = 18; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·18·(-10)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*18}=\frac{-24}{36}
=-2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*18}=\frac{30}{36}
=5/6
$