(3a+2)(6a+7)=

Solution for (3a+2)(6a+7)= equation:

(3a+2)(6a+7)=

We move all terms to the left:

(3a+2)(6a+7)-()=0

We add all the numbers together, and all the variables

(3a+2)(6a+7)=0

We multiply parentheses ..

(+18a^2+21a+12a+14)=0

We get rid of parentheses

18a^2+21a+12a+14=0

We add all the numbers together, and all the variables

18a^2+33a+14=0

a = 18; b = 33; c = +14;
Δ = b2-4ac
Δ = 332-4·18·14
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-9}{2*18}=\frac{-42}{36}
=-1+1/6
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+9}{2*18}=\frac{-24}{36}
=-2/3
$