(36x2+42x-49)=0

Solution for (36x2+42x-49)=0 equation:

(36x^2+42x-49)=0

We get rid of parentheses

36x^2+42x-49=0

a = 36; b = 42; c = -49;
Δ = b2-4ac
Δ = 422-4·36·(-49)
Δ = 8820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8820}=\sqrt{1764*5}=\sqrt{1764}*\sqrt{5}=42\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42\sqrt{5}}{2*36}=\frac{-42-42\sqrt{5}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42\sqrt{5}}{2*36}=\frac{-42+42\sqrt{5}}{72}
$