(35-y)/2=(15+y)/3

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Solution for (35-y)/2=(15+y)/3 equation: 



(35-y)/2=(15+y)/3

We move all terms to the left:

(35-y)/2-((15+y)/3)=0

We add all the numbers together, and all the variables

(-1y+35)/2-((y+15)/3)=0

We calculate fractions


(-y)/()+(-((y+15)*2)/()=0



We calculate terms in parentheses: +(-((y+15)*2)/(), so:

-((y+15)*2)/(

We multiply all the terms by the denominator


-((y+15)*2)



We calculate terms in parentheses: -((y+15)*2), so:

(y+15)*2

We multiply parentheses

2y+30

Back to the equation:

-(2y+30)



We get rid of parentheses

-2y-30

Back to the equation:

+(-2y-30)



We add all the numbers together, and all the variables

(-1y)/()+(-2y-30)=0

We get rid of parentheses

(-1y)/()-2y-30=0

We multiply all the terms by the denominator


(-1y)-2y*()-30*()=0

We add all the numbers together, and all the variables

(-1y)-2y*()=0

We get rid of parentheses

-1y-2y*()=0

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