(35+3n)=(20+2n)

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Solution for (35+3n)=(20+2n) equation:



(35+3n)=(20+2n)
We move all terms to the left:
(35+3n)-((20+2n))=0
We add all the numbers together, and all the variables
(3n+35)-((2n+20))=0
We get rid of parentheses
3n-((2n+20))+35=0
We calculate terms in parentheses: -((2n+20)), so:
(2n+20)
We get rid of parentheses
2n+20
Back to the equation:
-(2n+20)
We get rid of parentheses
3n-2n-20+35=0
We add all the numbers together, and all the variables
n+15=0
We move all terms containing n to the left, all other terms to the right
n=-15

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