(34x-2)=(8x+(23x+10))

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Solution for (34x-2)=(8x+(23x+10)) equation: 



(34x-2)=(8x+(23x+10))

We move all terms to the left:

(34x-2)-((8x+(23x+10)))=0

We get rid of parentheses

34x-((8x+(23x+10)))-2=0



We calculate terms in parentheses: -((8x+(23x+10))), so:

(8x+(23x+10))



We calculate terms in parentheses: +(8x+(23x+10)), so:

8x+(23x+10)

We get rid of parentheses

8x+23x+10

We add all the numbers together, and all the variables

31x+10

Back to the equation:

+(31x+10)



We get rid of parentheses

31x+10

Back to the equation:

-(31x+10)



We get rid of parentheses

34x-31x-10-2=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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