(33x+35)(26x+49)=180

Solution for (33x+35)(26x+49)=180 equation:

(33x+35)(26x+49)=180

We move all terms to the left:

(33x+35)(26x+49)-(180)=0

We multiply parentheses ..

(+858x^2+1617x+910x+1715)-180=0

We get rid of parentheses

858x^2+1617x+910x+1715-180=0

We add all the numbers together, and all the variables

858x^2+2527x+1535=0

a = 858; b = 2527; c = +1535;
Δ = b2-4ac
Δ = 25272-4·858·1535
Δ = 1117609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2527)-\sqrt{1117609}}{2*858}=\frac{-2527-\sqrt{1117609}}{1716}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2527)+\sqrt{1117609}}{2*858}=\frac{-2527+\sqrt{1117609}}{1716}
$