(32-3y)=(2y+23)

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Solution for (32-3y)=(2y+23) equation: 



(32-3y)=(2y+23)

We move all terms to the left:

(32-3y)-((2y+23))=0

We add all the numbers together, and all the variables

(-3y+32)-((2y+23))=0

We get rid of parentheses

-3y-((2y+23))+32=0



We calculate terms in parentheses: -((2y+23)), so:

(2y+23)

We get rid of parentheses

2y+23

Back to the equation:

-(2y+23)



We get rid of parentheses

-3y-2y-23+32=0

We add all the numbers together, and all the variables

-5y+9=0

We move all terms containing y to the left, all other terms to the right

-5y=-9

y=-9/-5

y=1+4/5

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