(32-2x)(28-2x)=0

Solution for (32-2x)(28-2x)=0 equation:

(32-2x)(28-2x)=0

We add all the numbers together, and all the variables

(-2x+32)(-2x+28)=0

We multiply parentheses ..

(+4x^2-56x-64x+896)=0

We get rid of parentheses

4x^2-56x-64x+896=0

We add all the numbers together, and all the variables

4x^2-120x+896=0

a = 4; b = -120; c = +896;
Δ = b2-4ac
Δ = -1202-4·4·896
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-8}{2*4}=\frac{112}{8}
=14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+8}{2*4}=\frac{128}{8}
=16
$