(30x+24)/(3x-9)*(x-3)/(20x+16)

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Solution for (30x+24)/(3x-9)*(x-3)/(20x+16) equation: 


D( x )

20*x+16 = 0

3*x-9 = 0

20*x+16 = 0

20*x+16 = 0

20*x+16 = 0 // - 16

20*x = -16 // : 20

x = -16/20

x = -4/5

3*x-9 = 0

3*x-9 = 0

3*x-9 = 0 // + 9

3*x = 9 // : 3

x = 9/3

x = 3

x in (-oo:-4/5) U (-4/5:3) U (3:+oo)

(((30*x+24)/(3*x-9))*(x-3))/(20*x+16) = 0

((30*x+24)*(x-3))/((3*x-9)*(20*x+16)) = 0

( 30*x+24 )

30*x+24 = 0 // - 24

30*x = -24 // : 30

x = -24/30

x = -4/5

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -4/5} 

x in { 3} 

x belongs to the empty set

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