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(30-2x)(20-2x)=184
We move all terms to the left:
(30-2x)(20-2x)-(184)=0
We add all the numbers together, and all the variables
(-2x+30)(-2x+20)-184=0
We multiply parentheses ..
(+4x^2-40x-60x+600)-184=0
We get rid of parentheses
4x^2-40x-60x+600-184=0
We add all the numbers together, and all the variables
4x^2-100x+416=0
a = 4; b = -100; c = +416;
Δ = b2-4ac
Δ = -1002-4·4·416
Δ = 3344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3344}=\sqrt{16*209}=\sqrt{16}*\sqrt{209}=4\sqrt{209}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-4\sqrt{209}}{2*4}=\frac{100-4\sqrt{209}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+4\sqrt{209}}{2*4}=\frac{100+4\sqrt{209}}{8} $
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