(30-12b/2)+5b=3

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Solution for (30-12b/2)+5b=3 equation: 


b in (-oo:+oo)

5*b-((12*b)/2)+30 = 3 // - 3

5*b-((12*b)/2)-3+30 = 0

5*b-6*b-3+30 = 0

27-b = 0 // - 27

-b = -27 // * -1

b = 27

b = 27

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